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x^2-0.75x-0.0145=0
a = 1; b = -0.75; c = -0.0145;
Δ = b2-4ac
Δ = -0.752-4·1·(-0.0145)
Δ = 0.6205
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.75)-\sqrt{0.6205}}{2*1}=\frac{0.75-\sqrt{0.6205}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.75)+\sqrt{0.6205}}{2*1}=\frac{0.75+\sqrt{0.6205}}{2} $
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